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通道查询排序输出,避免列表杂乱无章

pull/38/head
Lawrence 4 years ago
parent
commit
f34eb9c9e6
  1. 2
      src/main/java/com/genersoft/iot/vmp/storager/dao/DeviceChannelMapper.java

2
src/main/java/com/genersoft/iot/vmp/storager/dao/DeviceChannelMapper.java

@ -63,6 +63,7 @@ public interface DeviceChannelMapper {
" WHERE 1=1 " + " WHERE 1=1 " +
" <if test=\"hasSubChannel == true\" > AND subCount >0</if>" + " <if test=\"hasSubChannel == true\" > AND subCount >0</if>" +
" <if test=\"hasSubChannel == false\" > AND subCount=0</if>" + " <if test=\"hasSubChannel == false\" > AND subCount=0</if>" +
" ORDER BY channelId ASC" +
" </script>"}) " </script>"})
List<DeviceChannel> queryChannelsByDeviceId(String deviceId, String parentChannelId, String query, Boolean hasSubChannel, Boolean online); List<DeviceChannel> queryChannelsByDeviceId(String deviceId, String parentChannelId, String query, Boolean hasSubChannel, Boolean online);
@ -96,6 +97,7 @@ public interface DeviceChannelMapper {
" <if test=\"hasSubChannel!= null and hasSubChannel == false\" > AND subCount=0</if> " + " <if test=\"hasSubChannel!= null and hasSubChannel == false\" > AND subCount=0</if> " +
" <if test=\"platformId != null and inPlatform == true \" > AND platformId='${platformId}'</if> " + " <if test=\"platformId != null and inPlatform == true \" > AND platformId='${platformId}'</if> " +
" <if test=\"platformId != null and inPlatform == false \" > AND (platformId != '${platformId}' OR platformId is NULL ) </if> " + " <if test=\"platformId != null and inPlatform == false \" > AND (platformId != '${platformId}' OR platformId is NULL ) </if> " +
" ORDER BY deviceId, channelId ASC" +
" </script>"}) " </script>"})
List<ChannelReduce> queryChannelListInAll(String query, Boolean online, Boolean hasSubChannel, String platformId, Boolean inPlatform); List<ChannelReduce> queryChannelListInAll(String query, Boolean online, Boolean hasSubChannel, String platformId, Boolean inPlatform);

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